1/5t^2-25-0

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Solution for 1/5t^2-25-0 equation: 


t in (-oo:+oo)

(1/5)*t^2-25+0 = 0

(1/5)*t^2-25 = 0

1/5*t^2 = 25 // : 1/5

t^2 = 125

t^2 = 125 // ^ 1/2

abs(t) = 5*5^(1/2)

t = 5*5^(1/2) or t = -(5*5^(1/2))

t in { 5*5^(1/2), -(5*5^(1/2)) }

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